<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:wfw="http://wellformedweb.org/CommentAPI/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:slash="http://purl.org/rss/1.0/modules/slash/"
	xmlns:georss="http://www.georss.org/georss" xmlns:geo="http://www.w3.org/2003/01/geo/wgs84_pos#" xmlns:media="http://search.yahoo.com/mrss/"
	>

<channel>
	<title>Hrkg08&#039;s Weblog</title>
	<atom:link href="http://hrkg08.wordpress.com/feed/" rel="self" type="application/rss+xml" />
	<link>http://hrkg08.wordpress.com</link>
	<description>small thoughts about life</description>
	<lastBuildDate>Thu, 07 Jul 2011 06:52:44 +0000</lastBuildDate>
	<language>en</language>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.com/</generator>
<cloud domain='hrkg08.wordpress.com' port='80' path='/?rsscloud=notify' registerProcedure='' protocol='http-post' />
<image>
		<url>http://s2.wp.com/i/buttonw-com.png</url>
		<title>Hrkg08&#039;s Weblog</title>
		<link>http://hrkg08.wordpress.com</link>
	</image>
	<atom:link rel="search" type="application/opensearchdescription+xml" href="http://hrkg08.wordpress.com/osd.xml" title="Hrkg08&#039;s Weblog" />
	<atom:link rel='hub' href='http://hrkg08.wordpress.com/?pushpress=hub'/>
		<item>
		<title>Concrete Mix Design</title>
		<link>http://hrkg08.wordpress.com/2008/09/23/novices-wisdom/</link>
		<comments>http://hrkg08.wordpress.com/2008/09/23/novices-wisdom/#comments</comments>
		<pubDate>Tue, 23 Sep 2008 15:23:00 +0000</pubDate>
		<dc:creator>hrkg</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://hrkg08.wordpress.com/?p=3</guid>
		<description><![CDATA[Here a typical practical Concrete Mix Designing procedure adopted at Indian construction sites has been explained for construction engineers for quick reference &#38; use. This provides a highly practical basic frame or guidelines for the same in an easy-to-understand manner.  There could be minor differences in the steps here &#38; there from site to site. [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=hrkg08.wordpress.com&amp;blog=4952444&amp;post=3&amp;subd=hrkg08&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><span style="font-family:Times New Roman;font-size:small;">Here a typical practical Concrete Mix Designing procedure adopted at Indian construction sites has been explained for construction engineers for quick reference &amp; use. This provides a highly practical basic frame or guidelines for the same in an easy-to-understand manner.  There could be minor differences in the steps here &amp; there from site to site.</span></p>
<p><span style="font-size:small;"><strong><span style="text-decoration:underline;"><span style="font-family:Times New Roman;">A Typical Mix-Design procedure for say, M40 (40 N/mm</span></span></strong><strong><span style="text-decoration:underline;">²)<span style="font-family:Times New Roman;"> Grade of Concrete.</span></span></strong></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">The Codes generally used are IS-456, IS-9103 &amp; SP-23 (latest versions) along with relevant contract specs.</span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">1)</span>      <span style="font-size:small;">Design Stipulation:</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">a)</span>      <span style="font-size:small;">f<sub>ck </sub>at 28 days = 40 N/mm<sup>2</sup></span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">b)</span>      <span style="font-size:small;">Max. size of aggregates = 20mm</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">c)</span>      <span style="font-size:small;">Degree of workability = Compaction Factor of 0.95 &amp; Slump of 100 to 150 mm as per IS-456.</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">d)</span>      <span style="font-size:small;">Shape of aggregates = angular </span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">e)</span>      <span style="font-size:small;">Degree of Quality Control = very good </span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">f)</span>       <span style="font-size:small;">Type of exposure = Moderate (or choose as per site condition)</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">g)</span>      <span style="font-size:small;">Max. water/cement (w/c) ratio = 0.50 (refer IS-456)</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">h)</span>      <span style="font-size:small;">Minimum cement content = say 300 kg ( refer IS-456 &amp; contract specification &amp; adopt the higher of the two)</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Note: In this design, coarse aggregates considered is a blend of 20mm as well as 12 mm aggregates blended at a ration of 60:40 i.e. 60% 20mm &amp; 40% 12mm aggregates. This is a commonly adopted practice in various sites. In stead of 12mm, some use 12.5mm or 10mm aggregates also. </span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">2)</span>      <span style="font-size:small;">Test data for materials:</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">a)</span>      <span style="font-size:small;">Grade of cement = OPC 43 grade (commonly used)</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">b)</span>      <span style="font-size:small;">Specific gravity of cement = say, 3.15</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">c)</span>      <span style="font-size:small;">Size of coarse aggregates = 20mm; Specific gravity of C.A. = say, 2.9; Water absorption = say, 0.45% (actual sp. gr. &amp; water absorption are to be determined at site-laboratory periodically as per Inspection Test Plan)</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">d)</span>      <span style="font-size:small;">Size of coarse aggregates = 12mm; Specific gravity of C.A. = say, 2.87; Water absorption = say, 0.75% (actual sp. gr. &amp; water absorption are to be determined at site laboratory periodically as per Inspection Test Plan)</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">e)</span>      <span style="font-size:small;">Fine aggregates used is River sand of say, Zone-1. Specific gravity of F.A. = say, 2.65; Water absorption = say, 1.15% (actual sp. gr. &amp; water absorption are to be determined at site laboratory periodically as per Inspection Test Plan)</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">3)</span>      <span style="font-size:small;">Mix calculation:</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">a)</span>      <span style="font-size:small;">Target Mean Strength = f<sub>ck^ </sub>=  f<sub>ck  </sub>+ 1.65S = 40 + 1.65 x 5 = 48.25 N/mm<sup>2</sup> </span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Where S is a factor specified for various degree of Quality Control &amp; in this case, for degree of quality control = very high, S = 5.</span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">b)</span>      <span style="font-size:small;">As per SP-23, for 20mm down coarse aggregates &amp; Zone-II fine aggregates water required for the mix is 180 litres &amp; percentage of fine aggregates is 25% for w/c ratio 0.35 &amp; C.F. 0.80. (Note that these are the standards stipulations and any variation from these would need correction as described below. The actual site conditions will generally always vary from these stipulations e.g. in stead of ideal Zone-II sand, only Zone-I or Zone-III sands are available in site, or the w/c ration adopted at site is 0.40 in stead of 0.35 as stipulated above etc. So, that’s okay as long as the necessary correction are induced)</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">After the above three steps one can proceed to the Trial-mix stage in order to arrive at the right or optimum mix-design for the particular mix, in this case M40. For that, several trials (usually 3 to 4) are conducted at laboratory adopting various w/c ratio &amp; cement contents on trial basis as described below:</span></p>
<p><span style="text-decoration:underline;"><span style="font-size:small;"><span style="font-family:Times New Roman;">Trial-Mix No.-1</span></span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">a)</span>      <span style="font-size:small;">w/c ratio:  Let us adopt a  w/c ratio of  0.37 (it is less than max. w/c ratio prescribed by IS-456 which is 0.50 in this case and hence safe). So, the w/c ratio is now 0.37, sand is Zone-I &amp; C.F. is 0.95 (refer Design Stipulation above). But the standard conditions mentioned as in point b) above are w/c of 0.35 &amp; sand of ideal Zone-II. Hence, some corrections need to be done as specified by the code itself:</span></span></p>
<p>&nbsp;</p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">                                                                     <span style="text-decoration:underline;">Water content</span>                       <span style="text-decoration:underline;">% of sand</span></span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">For sand conforming to Zone-I                           0                                   (+)1.5%</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">For increase of C.F by 0.15                             (+) 4.5%                                 0</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">(0.95 &#8211; 0.80 = 0.15)</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">For increase in w/c ratio by 0.02                         0                                   (+) 0.4%</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">(0.37 – 0.35 = 0.02)</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Net correction to be induced =                        (+) 4.5%                           (+)1.9%</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Therefore, % of sand 25 + 1.9 = 26.9%</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">As a result, % of C.A. = 100 – 26.9 = 73.1%</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">In case of concrete to be poured by pumping &amp; not manually, then it is convenient to reduce C.A. by 10% as per ACI 221 for practical reasons. This correction need not be done for manually poured concrete. In this case, pumped concrete is considered.</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Therefore, modified % of C.A. now comes to = 73.1 – 10% of 73.1 = 65.79%</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Accordingly, modified % of C.A. now comes to = 100 – 65.79 = 34.21% = say, 34%.</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Now, referring to the all-in-one aggregates combined curve, it suggests a slightly high 37% of  F.A.(sand) for reasons like better pumpability and cohesiveness. This is also called the ratio of F.A. to total aggregates i.e. 0.37.</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Now, corrected Water Content = 180 + 4.5% of 180 = 180 + 8.1 = 188.1 liters.</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">According to IS-9103 &amp; ASTM-C494, with addition of super plasticisers water content can be reduced by 20 to 25% with a dosage of 0.9 to 1.2% of the cement content. This is convenient as lesser w/c is desirable for higher strength and at the same time it ensures desired workability as well.</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Let water content reduction of 20% be considered for strength purpose by addition of 1% super plasticiser,</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Hence, final water content = 188.1 – 20% of 188.1 = 150.48 = say 150 liters or kg.</span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">b)</span>      <span style="font-size:small;">Cement content = (water content)/(w.c ratio) = 150/0.37 = 405.41 kg.</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">This is higher than minimum cement content, 300 kg, required for M40 as per IS-456, hence safe. If contract specification asks for a higher min. content then in stead of 300kg, that figure needs to be considered for min content check purpose, A higher figure than the calculated one could be adopted to be on the safer side. In this case, calculated fig. is 405.41 kg &amp; let 425 kg be the adopted cement content.</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">So, for the finally adopted cement content of 425 kg, the actual water content would be now = 425 x w/c ratio = 425 x 0.37 = 157.25 liters or kg. </span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">c)</span>      <span style="font-size:small;">As per SP-23, Volume of entrapped air in 1 M<sup>3 </sup>of fresh concrete for 20mm max. size C.A. = 2%. </span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Hence, Absolute volume of  1 M<sup>3 </sup>fresh concrete = gross vol. of 1 M<sup>3 </sup>of fresh concrete – entrapped air (i.e. 2% of 1 M<sup>3</sup>) = 0.98 M<sup>3 </sup>.</span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">d)</span>      <span style="font-size:small;">Calculation of Volumes of F.A. &amp; C.A.:</span></span></p>
<p>&nbsp;</p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">      V= [ W + </span>C/S<sub>c </sub><span style="font-family:Times New Roman;">+ A/</span>S<sub>a </sub><span style="font-family:Times New Roman;">+ 1/P x F<sub>a</sub>/S<sub>fa</sub> ] x 1/1000  ………… Eq.1</span></span></p>
<p>&nbsp;</p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">      V= [ W + </span>C/S<sub>c </sub><span style="font-family:Times New Roman;">+ A/</span>S<sub>a </sub><span style="font-family:Times New Roman;">+ 1/(1-P) x C<sub>a</sub>/S<sub>ca</sub> ] x 1/1000  ……&#8230;Eq.2</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">Where, V= Absolute vol. of 1 M<sup>3 </sup>fresh concrete =  0.98 M<sup>3 </sup><sub>     </sub></span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">      W = mass of water per M<sup>3 </sup>of concrete = 425 x 0.37 = 157.25.</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">       C = mass of cement per M<sup>3 </sup>of concrete = 425kg.</span></span></p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">       </span>S<sub>c </sub><span style="font-family:Times New Roman;">= specific gravity of cement = say, 3.15.</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">       A = mass of admixture = 4.25kg.</span></span></p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">       </span>S<sub>a </sub><span style="font-family:Times New Roman;">= specific gravity of admixture(super plasticiser) = say, 1.18.</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">       P = ratio of F.A. to total aggregates = 0.37.</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">       S<sub>fa </sub>= specific gravity of F.A. in saturated surface dry (S.S.D.) condition = say, 2.65.</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">       S<sub>ca </sub>= sp.gr. of C.A. in saturated surface dry (S.S.D.) condition = say,2.89(for 20mm)</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">                                                                                                                    = say,2.87(for 12mm)</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Now, for F.A., putting values in Eq.1,</span></p>
<p>&nbsp;</p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">          V =  [W + </span>C/S<sub>c </sub><span style="font-family:Times New Roman;">+ A/</span>S<sub>a </sub><span style="font-family:Times New Roman;">+ 1/P x F<sub>a</sub>/S<sub>fa</sub> ] x 1/1000</span></span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">   i.e.  0.98 = [157.25 + 425/3.15 + 4.25/1.18 + 1/0.37 x F<sub>a</sub>/2.65] x 1/1000.</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Hence,  F<sub>a</sub> = say, 684 kg</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">for C.A. proportion of 20mm &amp; 12mm aggregates in the combined grading is 60:40.</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Hence, for C.A., putting values in Eq.2,</span></p>
<p>&nbsp;</p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">           V= [ W + </span>C/S<sub>c </sub><span style="font-family:Times New Roman;">+ A/</span>S<sub>a </sub><span style="font-family:Times New Roman;">+ 1/(1-P) x C<sub>a</sub>/S<sub>ca</sub> ] x 1/1000</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">For 20mm,  0.98 = [157.25 + 425/3.15 + 4.25/1.18 + 1/0.63*.60 x C<sub>a</sub>/2.89] x 1/1000</span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">           C<sub>a </sub>= say, 747 kg (20mm)</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">For 12mm,  0.98 = [157.25 + 425/3.15 + 4.25/1.18 + 1/0.63*.40 x C<sub>a</sub>/2.87] x 1/1000</span></p>
<p><span style="font-family:Times New Roman;"><span style="font-size:small;">           C<sub>a </sub>= say, 495 kg (12mm).</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">So, mix details for Trial Mix No.1:</span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Cement = 425 kg,  Water = 157.25 liters or kg,  20mm CA = 747 kg,  12mm CA = 495 kg,  F.A. = 684 kg,  Admixture = 4.25 kg.</span></p>
<p><span style="text-decoration:underline;"><span style="font-family:Times New Roman;"><span style="font-size:small;">Trial-Mix No.-2:</span></span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">For trial 2, consider a w/c ratio of say, 0.36 &amp; a cement content of say, 435 kg. Then all the steps for TM No.1 are to be repeated and the above quantities are to be arrived at.</span></p>
<p><span style="text-decoration:underline;"><span style="font-family:Times New Roman;"><span style="font-size:small;">Trial-Mix No.-3:</span></span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;">For trial 3, consider a w/c ratio of say, 0.37 &amp; a cement content of say, 415 kg. Then all the steps for TM No.1 are to be repeated and the above quantities are to be arrived at. </span></p>
<p><span style="font-family:Times New Roman;font-size:small;">Similarly any number of trials can be done by repeating the above procedure. Generally 3 trials are sufficient.</span></p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">Now, for all the above three trials cube tests are conducted in laboratory to determine the 7 days &amp; 28 days strengths for each trial mix. The results should meet the strength requirement i.e. the 28 days cube strength should be at least f<sub>ck^ </sub>which is 48.25 N/mm<sup>2 </sup>as calculated in the beginning in this case. The 7 days strength should not be less than </span>⅔<span style="font-family:Times New Roman;"> times the 28 days strength. Adopt the mix which meets both the criteria as the final mix for the purpose of casting. In case all the trials meet the strength criteria, then the one with the least cement content (in this case TM No.3) could be adopted as it would be economic.</span></span></p>
<p><span style="font-size:small;"><span style="font-family:Times New Roman;">Finally, Batch Correction needs to be done as in the above equations i.e. Eq.1 &amp; Eq.2, the aggregates are assumed to be in Saturated Surface Dry (SSD) condition i.e. they are fully saturated &amp; hence can not absorb any further water when aggregates are mixed with water in plants or mixture machines. In reality that is not the case and both CA &amp; FA will hardly be fully saturated and hence would suck water from the added quantity of water &amp; thus changing the w/c ratio. To avoid that batch correction is necessary &amp; for that actual moisture contents of all the aggregates are determined in laboratory for all the trial mixes. Then correction is done as shown in the table below:</span></span></p>
<p><span style="font-family:Times New Roman;font-size:small;"> </span></p>
<p><span style="font-family:Times New Roman;font-size:small;"> </span></p>
<p><span style="font-family:Times New Roman;font-size:small;"> </span></p>
<br />  <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/hrkg08.wordpress.com/3/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/hrkg08.wordpress.com/3/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/hrkg08.wordpress.com/3/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/hrkg08.wordpress.com/3/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gofacebook/hrkg08.wordpress.com/3/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/facebook/hrkg08.wordpress.com/3/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gotwitter/hrkg08.wordpress.com/3/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/twitter/hrkg08.wordpress.com/3/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/hrkg08.wordpress.com/3/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/hrkg08.wordpress.com/3/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/hrkg08.wordpress.com/3/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/hrkg08.wordpress.com/3/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/hrkg08.wordpress.com/3/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/hrkg08.wordpress.com/3/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=hrkg08.wordpress.com&amp;blog=4952444&amp;post=3&amp;subd=hrkg08&amp;ref=&amp;feed=1" width="1" height="1" />]]></content:encoded>
			<wfw:commentRss>http://hrkg08.wordpress.com/2008/09/23/novices-wisdom/feed/</wfw:commentRss>
		<slash:comments>0</slash:comments>
	
		<media:content url="http://1.gravatar.com/avatar/10b96ef2ececb0daa91da2230d53fe07?s=96&#38;d=identicon&#38;r=G" medium="image">
			<media:title type="html">hrkg</media:title>
		</media:content>
	</item>
	</channel>
</rss>
